One day, how three beams of extreme light at equal angles meeting at a point interact may be resolved by simulation or experiment, but for now it must be envisaged. In the lepton case, two beams meeting head-on can complete the one channel set bandwidth of one node axis, as each contributes half a channel set. This gives the repeating overload we call matter and the charge remainders correctly for leptons and anti-leptons.
In the quark case, three beams meet in a node where again each provides half a channel set. To give stable matter by the same logic, the result must fill the channels of a plane not just a line. A node plane has two dimensions so its bandwidth is two channel sets. Dividing the two channel sets of a plane by three-axes of colliding photons means each collision axis fills at two-thirds of a channel set.
A tail-tail-tail meet isn’t possible as it implies a prior head-head-head event, so the phase options are:
1. Head-head-head. Three sets of photon heads meeting at equal angles in a node will allocate processing equally. Every axis is only partly filled so it has free channels that let other entities in so the result isn’t stable.
2. Head-tail-tail. Now two photon beams leave a node as another arrives, as shown in Figure 4.10a. For the reasons given next, this is proposed to be an up quark.
3. Head-head-tail. In this case one beam has passed through the node as the other two arrive, as shown in Figure 4.10b. For the reasons given next, this is proposed to be a down quark.
Of these options, the last two are proposed to be up and down quarks (Figure 4.10).